Yeah, it might be! But I prefer to try to find combos with all three filler leaves, because I'm kinda trying to find the balance that the whole tobacco plant is offering, and the ligero is bringing something different to the mix than the seco and the viso....
It's filler only.
That's really cool, Web. Yours is probably more useful for more people than what I'm going for, which is something that allows me to create a wide variety of flavor/strength profiles that all = 6, which always seems to result in a blend I really enjoy.
Hi, Marc L. Yeah, depending on what you mean by makes sense. I reckon anything makes sense when it comes to burning leaves. OTOH if you plugged that into my Bliss Balanced Blend formula you'd get something a little bit weak. You'd be left feeling it needed some punch. Assuming the Piloto is a seco with burn/flavor characteristics of Jorge seco, and the Criollo is viso, the Mata ligero... then very roughly you're looking at:
The idea with mine is to create a range of blends in order of strength which each add up to an input number of leaves, with each blends scoring a magic six. So if I am rolling a vitola which requires X number of leaves, I enter X, and I get back an array of portions of leaf I need to put in. Each ought to score six, once you total the number of each type leaf times your 1,2,3 score; but you're not looking at scores -- you're looking at leaf counts. I dunno. There's gotta be a better way to express that.
Well, your value counts don't all come up to 6; only the "balanced" one does. So it's working off a different concept. E.G. your "strong" blend = something like 7.75. That would be way too strong for me; it would be "an unbalanced strong blend."
How would you suggest solving the ratios?
I'm uploading a video now where I demo the machine to myself (otherwise I'm apt to wake up tomorrow and wonder how the f the thing was supposed to work) and the first thing I do there is make a "strongish balanced blend." I demo a few other blend constructions with it as well.
Abstractly, I'm providing a range of viable solutions for S(1)+V(2)+L(3) = 6, assuming 3 leaves.
I feel like there's something above I'm missing. maybe spell this out. (" S(1)+V(2)+L(3) = 6, assuming 3 leaves.") and, are you talking about that corona only?
I'm not thinking about vitolas, just leaf counts. I first start fleshing out the idea in a blog post a few days ago:
Nice, i was just trying to tackle this math problem and was getting stuck since it's a 3 variable issue. But setting a ratio of ligero to viso makes perfect sense and simplifies it!
Exactly. Once I realized that 1 seco would be a pretty common pivot, that left the viso/ligero ratio, which actually solved what I was trying to get at in the blend.
Very cool. So for my Corona that uses 2.5 leaves total... if i set my ligero at 0.5 leaves....
Yeah. You just have to keep balancing in two places. That's the thing I got from the article with the old Cuban roller gal from El Laguito. It's not just throw more at it, or take out some, it's "If you adjust this, then you have to adjust that, too. You have to maintain the balance."
